LinkedIn T-SQL Skill Assessment Answers (2024)

The LinkedIn Skill Assessments feature allows you to demonstrate your knowledge of the skills you’ve added on your profile. Job posters on LinkedIn can also add Skill Assessments as part of the job application process. This allows job posters to more efficiently and accurately verify the crucial skills a candidate should have for a role.

LinkedIn T-SQL Skill Assessment Answers
LinkedIn T-SQL Skill Assessment Answers

The topics in the T-SQL assessment include:

  • Writing queries
  • Data types
  • SQL syntax
  • Functions
  • Terminology
  • Query results
  • Join statements
  • Constraints, Indexes, and Keys
  • Database administration

Question Format

Multiple Choice

Language

English

Table of Content


LinkedIn T-SQL Skill Assessment Answers

Which answer is NOT a type of table index?

  • nonclustered
  • unique
  • heap
  • hash

The keywords AND, IN, LIKE, and between all belong to a category called what?

  • joining operations
  • linking operations
  • criteria operations
  • logical operations

What is the result of this series of statements?

BEGIN TRY
SELECT ‘Foo’ AS Result;
END TRY
BEGIN CATCH
SELECT ‘Bar’ AS Result;
END CATCH

  • Foo
  • FooBar
  • Foo Bar
  • Bar

Given these two tables, which query generates a listing showing student names and the department office location where you could reach each student?

  • SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students, Departments;
  • SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students JOIN Departments ON Students.department = Departments.department;
  • SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students JOIN Departments;
  • SELECT Students.first_name, Students.last_name, Departments.office_location FROM Students ON Students.department = Departments.department;

What is an example of a DDL command in SQL?

  • TRUNCATE TABLE
  • DELETE
  • MERGE
  • DROP

Given the Games table pictured, which query generates the results shown?

  • SELECT GameType, MaxPlayers, count(*) AS NumberOfGames FROM Games GROUP BY MaxPlayers, GameType ORDER BY MaxPlayers, GameType;
  • SELECT GameType, MaxPlayers, count(*) AS NumberOfGames FROM Games GROUP BY GameType, MaxPlayers ORDER BY GameType;
  • SELECT GameType, count(Players) AS MaxPlayers, NumberOfGames FROM Games GROUP BY GameType, MaxPlayers ORDER BY GameType;
  • SELECT GameType, MaxPlayers, count(*) AS NumberOfGames FROM Games GROUP BY GameType ORDER BY MaxPlayers;

Which answer is a possible result of the sequence of commands below?

DECLARE @UniqueID uniqueidentifier = NEWID();
SELECT @UniqueID AS Result;

  • …………………………………
  • bb261196-66a5-43af-815d-123fc593cf3a
  • z350mpj1-62lx-40ww-9ho0-4u1875rt2mx4
  • 0x2400001155F04846674AD4590F832C0

You need to find all students that are not on the “Chemistry Cats” team. Which query does NOT work for this task?

  • SELECT * FROM Students WHERE team NOT ‘Chemistry Cats’;
  • SELECT * FROM Students WHERE team <> ‘Chemistry Cats’;
  • SELECT * FROM Students WHERE team != ‘Chemistry Cats’;
  • SELECT * FROM Students WHERE NOT team = ‘Chemistry Cats’;

You need to write a query that returns all Employees that have a LastName starting with the letter A. Which WHERE clause should you use to fill in the blank in this query?

  • WHERE LastName = A*
  • WHERE LastName = LIKE ‘%A%’
  • WHERE LastName LIKE ‘A%’
  • WHERE LastName IN (‘A*’)

Which query shows the first name, department, and team of all students with the two lowest points?

  • SELECT LIMIT(2) first_name, department, team FROM Students ORDER BY points ASC;
  • SELECT TOP(2) first_name, deprtment, team FROM Students ORDER BY points DESC;
  • SELECT TOP(2) WITH TIES first_name, department, team FROM Students ORDER BY points;
  • SELECT BOTTOM(2) first_name, department, team FROM Students ORDER BY points ASC;

What is the result of this statement?
SELECT FLOOR(-1234.321)

  • -1234.3
  • -1234
  • -1235
  • 1234.321

Which is the best approach to update the last name of the student Donette Figgins to Smith?

  • UPDATE Students SET last_name = ‘Smith’ WHERE email = ‘[email protected]’;
  • UPDATE Students SET last_name = ‘Figgins’ WHERE email = ‘[email protected]’;
  • UPDATE Students SET last_name = ‘Figgins’ WHERE last_name = ‘Smith’ AND first-name = ‘Donette’;
  • UPDATE Students SET last_name = ‘Smith’ WHERE last_name = ‘Figgins’ AND first-name = ‘Donette’;

Which of these data types is an approximate numeric?

  • real
  • bit
  • decimal
  • numeric

You need to remove all data from a table name Products. Which query fully logs the removal of each record?

  • TRUNCATE FROM Products *;
  • DELETE FROM Products;
  • DELETE * FROM Products;
  • TRUNCATE TABLE Products;

What is the result of the following query? SELECT 1 / 2 AS Result;

  • 0.5
  • error
  • 0
  • 2

which data type will most efficiently store a person’s age in years?

  • float
  • int
  • tinyint
  • bigint

What is the result of this query?

SELECT ‘abc\
def’ AS Result;

  • abc\def
  • abcdef
  • error
  • abc def

To select a random student from the table, which statement could you use?

  • SELECT TOP(1) first_name, last_name FROM Students ORDER BY NEWID();
  • SELECT TOP(1) RAND(first_name, last_name) FROM Student;
  • SELECT TOP(1) first_name, last_name FROM Student;
  • SELECT TOP(1) first_name, last_name FROM RAND(Student);

What result is returned after executing the following commands?

DECLARE @MyVariable int;
SET @MyVariable = 1;
GO
SELECT @MyVariable;

  • error
  • 1
  • null
  • @MyVariable

Which statement creates a new database schema named Sales and establish Sharon as the owner?

  • ALTER USER Sharon WITH DEFAULT_SCHEMA = Sales;
  • ALTER USER Sharon SET SCHEMA Sales;
  • CREATE SCHEMA Sales SET OWNER Sharon;
  • CREATE SCHEMA Sales AUTHORIZATION Sharon;

The result of a CROSS JOIN between a table with 4 rows, and one with 5 rows, will give with _ rows.

  • 1024
  • 20
  • 0
  • 9

You need to write a query that returns all products that have a SerialNumber ending with “10_3”. Which WHERE clause should you use to fill in the blank in this query?

SELECT ProductID, ProductName, SerialNumber
FROM Products______ ;

  • WHERE SerialNumer LIKE ‘%10_3’
  • WHERE SerialNumer LIKE (‘%10’+’_’+’3’)
  • WHERE SerialNumer LIKE ‘%10″_”3’
  • WHERE SerialNumer LIKE ‘%10[_]3’

When no join type between multiple tables in a query’s FROM clause is specified, what type of join is assumed?

  • INNER
  • RIGHT
  • LEFT
  • FULL

How many bytes of storage does the int data type consume?

  • 1 byte
  • 2 bytes
  • 4 bytes
  • 8 bytes

What does a RIGHT JOIN ensure?

  • that only records from the rightmost table will be displayed
  • that no records from the rightmost table are displayed if the records dont have corresponding records in the left table
  • that records from the rightmost table will be displayed only if the records have a corresponding value in the leftmost table
  • that all records from the rightmost table are represented in the result, even if there are no corresponding records in the left table

You execute the following three queries. What is the result?

Create table students(id int identity(1000,1), firstname varchar(20),
lastname varchar(30));
insert into students(firstname,lastname)values(‘mark’,’twain’);
select * from students;

  • studentid firstname lastname 1 1001 mark twain
  • studentid firstname lastname 1 1 mark twain
  • studentid firstname lastname 1 1000 mark twain
  • studentid firstname lastname 1 null mark twain

Which Query returns all student names with the highest grade?
create table students( studentname varchar(50), grade int);

  • select studentname from students where grade=max(grade);
  • select top(1) studentname from students order by grade;
  • select top(1) with ties studentname from students order by grade desc;
  • select studentname,max(grade) from students order by grade desc;

What role does “inventory” play?
select bookid, boooktitle, bookauthor,quantityonhand from inventory.books;

  • you only want to see results from books currently in inventory
  • it instructs the query engine to find the books table in the inventory schema
  • it instructs the query engine to find the books table in the inventory database
  • it instructs the query engine to join the books table to the inventory schema

What is the result of an INNER JOIN between table1 and table2?

  • Only records that have corresponding entries in table1 and table2 are displayed.
  • No records from table1 are ever displayed.
  • All records from table1 are displayed, regardless of whether the records have a corresponding row in table2
  • Only records that have no corresponding records in table1 or table2 are displayed.

To remove all of the content from the Students table but keep the schema, which statement should you use?

  • TRUNCATE TABLE Students;
  • TRUNCATE * FROM Students;
  • DROP TABLE Students;
  • REMOVE * FROM Students;

Review the CREATE TABLE statement below. Which option, when placed in the blank space, ensures that the BookISBN column will not contain any duplicate values?

CREATE TABLE Books (
BookID int PRIMARY KEY,
BookISBN char(13) NOT NULL _,
BookTitle nvarchar(100) NOT NULL
);

  • NO DUPLICATES
  • UNIQUE CONSTRAINT AK_Books_BookISBN
  • DUPLICATE CONSTRAINT (AK_Books_BookISBN)
  • CONSTRAINT AK_Books_BookISBN UNIQUE

Given a table with the following structure, which query will not return the lowest grade earned by any student?

CREATE TABLE Students (
StudentName varchar(50),
Grade int
);

  • A
    SELECT StudentName
    FROM Students
    WHERE Grade = (SELECT MIN(Grade) FROM Student);
  • B
    SELECT TOP(1) Grade
    FROM Students
    ORDER BY Grade;
  • C
    SELECT MIN(Grade
    FROM Students
    ORDER BY Grade;

  • D
    SELECT MIN(Grade)
    FROM Students

Given a table with the following structure, which query will not return the lowest grade earned by any student?

  • UPDATE Students SET last_name=’Smith’, email = ‘[email protected]’ WHERE id=’56295′;
  • UPDATE Students SET last_name=’Smith’ AND email = ‘[email protected]’ WHERE id=’56295′;
  • UPDATE Students SET last_name=’Smith’ AND email = ‘[email protected]’ WHERE id=56295;
  • UPDATE Students SET last_name=’Smith’, email = ‘[email protected]’ WHERE id=56295;

You would like to have a record added to a TableB every time a record is modified in TableA. What technique should you look at implementing?

  • You should create a DML trigger on the server.
  • You should create a DDL trigger on the database.
  • You should create a DML trigger on TableA.
  • You should create a DML trigger on TableB.

What is the problem with this code?

DECLARE @Counter int;
SET @Counter = 1;
WHILE @Counter > 0
BEGIN
SET @Counter = @Counter +1;
END;

  • There is no END WHILE statement;
  • The local varaible is not available to the WHILE block.
  • The query causes an infinite loop.
  • “Counter” is an invalid variable name.

Which is the right query to change the name of the Philosophy Pandas team to the Philosophy Parrots?

  • UPDATES Students SET team = ‘Philosophy Parrots’ WHERE team = ‘Philosophy Pandas’;
  • UPDATES Students SET team = “Philosophy Parrots” WHERE team = ‘Philosophy Pandas’;
  • UPDATES Students SET team = “Philosophy Parrots” WHERE team = “Philosophy Pandas”;
  • UPDATES Students SET team = Philosophy Parrots WHERE team = Philosophy Pandas;

What is the result of this query?
SELECT ‘123’+’123′ AS Result;

  • error
  • ‘123”123’
  • 123123
  • 246

To combine the results of two or more SELECT statements, removing duplicates, which keyword can you use?

  • DEDUPE
  • SELECT
  • MERGE
  • UNION

You run this series of statements. What is the final result?

CREATE TABLE MyTable (MyValue int);
INSERT INTO MyTable VALUES (1);
WHILE (SELECT MyValue FROM MyTable) < 5
BEGIN
UPDATE My Table SET MyValue = MyValue + 1;
END;
SELECT MyValue AS Result FROM MyTable;

  • 5
  • error
  • 1
  • 6

Is there an error with this query? If so, which statement best describes the problem?

SELECT OrderID, SUM(LineTotal) AS SubTotal
FROM Sales
WHERE SUM(LineTotal) > 1000
GROUP BY OrderID
ORDER BY OrderID;

  • Yes, a WHERE clause cannot be used with an aggregate function.
  • Yes, you cannot GROUP BY and ORDER BY the same field.
  • No, there is nothing wrong with this query.
  • Yes, the WHERE clause should use the SubTotal alias.

You created the two tables below. Later, you decide that you want the database to remove all books from the Books table if the related publisher is deleted from the Publishers table. What command should you run?

CREATE TABLE Books (
BookID int PRIMARY KEY,
BookTitle nvarchar(100) NOT NULL,
PublisherID int NOT NULL
);
CREATE TABLE Publishers (
PublisherID int PRIMARY KEY,
PublisherName nvarchar(50)
)

  • A
    ADD CONSTRAINT FK Books_PublisherID
    FOREIGN KEY (PublisherID)
    REFERENCES Publishers (PublisherID) ON UPDATE SET NULL
  • B
    ADD CONSTRAINT FK Books_PublisherID
    FOREIGN KEY (PublisherID)
    REFERENCES Publishers (PublisherID) ON DELETE CASCADE

  • C
    ADD CONSTRAINT FK_Books_PublisherID
    FOREIGN KEY (PublisherID)
    REFERENCES Publishers (PublisherID)
  • D

    ADD CONSTRAINT FK_Publishers_PublisherID
    FOREIGN KEY (PublisherID)
    REFERENCES Books (PublisherID) CASCADE DELETE

Your database currently has a table called Inventory in the Warehouse schema. You need to move the table to the Products schema. Which query accomplishes this goal?

  • ALTER SCHEMA Products TRANSFER Warehouse.Inventory;
  • ALTER TABLE Warehouse.Inventory TRANSFER Products.Inventory;
  • ALTER TABLE Warehouse.Inventory ADD SCHEMA Products;
  • ALTER SCHEMA Warehouse ADD TABLE Inventory;

Which option—when placed in the blank space — establishes the PersonlD column as the primary key for the table with a nonclustered index?

CREATE TABLE People (
PersonID int NOT NULL,
PersonName nvarchar(50),
———–
);

  • INDEX ON PersonID (PRIMARY KEY PK_People)
  • ADD NONCLUSTERED PRIMARY KEY CONSTRAINT PK_People ON PersonID
  • CONSTRAINT PK_People PRIMARY KEY NONCLUSTERED (PersonID)
  • PRIMARY KEY CONSTRAINT (PersonID) NONCLUSTERED INDEX

Which statement could you use to select a random student from this table?

  • SELECT TOP(1) first_name, last_name FROM Students ORDER BY NEWID();
  • SELECT TOP(1) RAND(first_name, last_name) FROM Student;
  • SELECT TOP(1) first_name, last_name FROM Student;
  • SELECT TOP(1) first_name, last_name FROM RAND(Student);

You need to create a simple database backup in the server’s Z:\Backups directory. Which query should you use?

  • BACKUP MyDatabase TO LOCATION = ‘Z:\Backups\MyDatabase.bak’;
  • CREATE BACKUP (DATABASE = ‘MyDatabase’ TO DISK = ‘Z:\Backups\MyDatabase. bak’);
  • BACKUP DATABASE MyDatabase ON ‘Z:\Backups\MyDatabase.bak’;
  • BACKUP DATABASE MyDatabase TO DISK = ‘z:\Backups\MyDatabase.bak’;

Suppose you want to have the name of a transaction called myTransaction recorded in the transaction log. Which statement represents the best way to accomplish this?

  • BEGIN TRAN myTransaction BEGIN LOG;
  • BEGIN TRAN myTransaction WITH LOG;
  • BEGIN TRAN myTransaction WITH MARK;
  • BEGIN TRAN WITH MARK myTransaction;

Though not currently a requirement, what will a future release of SQL Server require of all SQL statements?Though not currently a requirement, what will a future release of SQL Server require of all SQL statements?

  • All statements must end with a semicolon.
  • All statements must operate on a table of data.
  • All statements must always be written in uppercase letters.
  • All statements must include more than one variable.

Which is the best approach to update the last name and email address of a student with ID 56295?

  • UPDATE Students SET last_name=’Smith’, email = ‘[email protected]’ WHERE id=’56295′;
  • UPDATE Students SET last_name=’Smith’, email = ‘[email protected]’ WHERE id=56295;
  • UPDATE Students SET last_name=’Smith’ AND email = ‘[email protected]’ WHERE id=56295;
  • UPDATE Students SET last_name=’Smith’ AND email = ‘[email protected]’ WHERE id=’56295′;

What is the result of this query?

SELECT 123+’abc’ AS Result;

  • 123abc
  • 123’abc’
  • ‘123abc’
  • error

What output will the following SQL sequence produce? Assume that the tables have been created and all the columns exist.

INSERT INTO Account (acct,bal) VALUES (‘12345’, 100);
UPDATE Account SET bal=bal+100;
BEGIN;
UPDATE Account SET bal=bal+100.
ROLLBACK;
SELECT bal FROM Account WHERE acct=’12345′;
);

  • 100
  • 200
  • 300
  • You will get an error because ROLLBACK deletes the row that was update

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